2[p+1]=3[p+1]

Solution for 2[p+1]=3[p+1] equation:

Simplifying
2[p + 1] = 3[p + 1]

Reorder the terms:
2[1 + p] = 3[p + 1]
[1 * 2 + p * 2] = 3[p + 1]
[2 + 2p] = 3[p + 1]

Reorder the terms:
2 + 2p = 3[1 + p]
2 + 2p = [1 * 3 + p * 3]
2 + 2p = [3 + 3p]

Solving
2 + 2p = 3 + 3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-3p' to each side of the equation.
2 + 2p + -3p = 3 + 3p + -3p

Combine like terms: 2p + -3p = -1p
2 + -1p = 3 + 3p + -3p

Combine like terms: 3p + -3p = 0
2 + -1p = 3 + 0
2 + -1p = 3

Add '-2' to each side of the equation.
2 + -2 + -1p = 3 + -2

Combine like terms: 2 + -2 = 0
0 + -1p = 3 + -2
-1p = 3 + -2

Combine like terms: 3 + -2 = 1
-1p = 1

Divide each side by '-1'.
p = -1

Simplifying
p = -1